Full Idea
It is a common mistake to render 'some Frenchmen are generous' by (∃x)(Fx→Gx) rather than the correct (∃x)(Fx&Gx). 'All Frenchmen are generous' is properly rendered by a conditional, and true if there are no Frenchmen.
Gist of Idea
'Some Frenchmen are generous' is rendered by (∃x)(Fx→Gx), and not with the conditional →
Source
E.J. Lemmon (Beginning Logic [1965], 3.1)
Book Reference
Lemmon,E.J.: 'Beginning Logic' [Nelson 1979], p.97
A Reaction
The existential quantifier implies the existence of an x, but the universal quantifier does not.